Posts

Featured post

Integration Calculus Lecture 02 Notes || Chapter 01 Module 03 For polytechnic

Image
 Adarsh Academy S - YouTube ( Subscribe )   Applied Mathematics - ll : Integration Calculus Lecture 02 Notes| Chapter 01 Module 03 For polytechnic Topics :- - Basic Introduction   Of Integration - Meaning Of Integration  - About Constant For Notes Pdf ;- Click For Download 

Previous Year Semester Exam Questions Paper ; Delhi Polytechnic

Image
 Adarsh Academy S - ( YouTube )  Previous Year Semester Exam Questions Paper ; Delhi Polytechnic  Subject List ;-  - Environment Studies  - Construction Material Previous Year Question Paper Pdf  Click for download 

Previous Year Semester Exam Questions Paper ; Delhi Polytechnic

Image
Adarsh Academy S - ( YouTube )  Previous Year Semester Exam Questions Paper ; Delhi Polytechnic  Subject   List  ;-  - Applied Mathematics 02  - Applied Mechanics  - Engineering Drawing - English & Communication Skill 1  Previous Year Question Paper Click for download 

Maxima & Minima - Second Derivative Test| Ch 05 | Application Of Differentiation 08 Notes ; Polytechnic

Image
Adarsh Academy S - YouTube ( Subscribe ) Maxima & Minima - Second Derivative Test| Ch 05 | Application Of Differentiation 07 Notes ; Polytechnic Hey Everyone, How are you ... Today I will show you How to Solve Words Problem related to Maxima & Minima , which is chapter 06 , Application Of Differentiation ( Derivatives ), Which Is Module 02 Of Applied mathematics 02  - Lecture 08 ( Topics ) : 1 ) Maxima & Minima - Words Problem.  2 ) Some Important Questions  3 ) Lecture Related Questions. 1 ) Maxima & Minima - Words Problem - Step Required To Find Maxima & Minima ; Step 01 ) F' ( x ) = 0  Step 02 ) Determine extreme Points . Step 03 ) Then Differentiate F'(x ) again And find second order derivatives. Step 04 ) Then Put the extreme point On f''(x )  Case l ) F''(x) |x=C1 <0 C1 Point of Maxima Case ll ) F'' (x ) | x = C2 > 0  Case lll ) F''(x) |x=C2 = 0 - Go to first Derivative test Check the sign of F'(x )  Step ...

Maxima & Minima - Second Derivative Test| Ch 05 | AOD 07 Notes.

Image
Adarsh Academy S - YouTube ( Subscribe ) Maxima & Minima - Second Derivative Test| Ch 05 | Application Of Differentiation 07 Notes ; Polytechnic Hey Everyone, How are you ... Today I will show you How to Find Maxima & Minima Of A Given Function by using Second derivative test , which is chapter 06 , Application Of Differentiation ( Derivatives ), Which Is Module 02 Of Applied mathematics 02  - Lecture 07 ( Topics ) : 1 ) Maxima & Minima - Second Derivative Test  2 ) Some Important Questions  3 ) Lecture Related Questions. 1 ) Maxima & Minima - Second Derivative Test . - Step Required To Find Maxima & Minima ; Step 01 ) F' ( x ) = 0  Step 02 ) Determine extreme Points . Step 03 )  Then Differentiate F'(x ) again And find second order derivatives. Step 04 )  Then Put the extreme point On f''(x )  Case l ) F''(x) |x=C1 <0 C1 Point of Maxima Case ll ) F'' (x ) | x = C2 > 0  Case lll ) F''(x) |x=C2 = 0 - Go to first Der...

Maxima & Minima - First Derivative Test| Ch 05 | Application Of Differentiation 06 Notes ; Polytechnic

Image
Adarsh Academy S - YouTube ( Subscribe ) Maxima & Minima - First Derivative Test| Ch 05 | Application Of Differentiation 06 Notes ; Polytechnic  Hey Everyone, How are you ... Today I will show you How to Find Maxima & Minima Of A Given Function by using first derivative test , which is chapter 06 , Application Of Differentiation ( Derivatives ), Which Is Module 02 Of Applied mathematics 02 . - Lecture 06 ( Topics ) : 1 ) Maxima & Minima - First Derivative Test  2 ) Some Important Questions . 3 ) Lecture Related Questions. 1 ) Maxima & Minima - First Derivative Test . - Step Required To Find Maxima & Minima ; Step 01 ) F' ( x ) = 0  Step 02 ) Allocate extreme Points on the number link  Step 03 ) Check the sign of F' ( x ) in each interval  Step 04 ) If Sign change positive to negative then value of x called point of Maxima  Step 05 ) If Sign change negative to positive then value of x called point of Minima Step 06 ) Then find maximum ...